Daily Drills 51 - Section 51 - Question 4

P: A → BP: ?C: C–some–B

rlquerubin December 30, 2019

Why not C some ~A?

I don't understand how you can successfully get to C some A. If you have C some B, can you say C some ~B? Because if some Cs are Bs, then at least one C is not a B (C some ~B). It would then follow that the transitive property has to point away from the quantifier which leads to C some ~A. P: A -> B P: ~B -> ~A P:? C: C some B C some ~B -> ~A C some ~A Thanks for your help.

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rlquerubin January 5, 2020

Is there a flaw in my logic?