If Q is in group 1 and S is in group 3, which one of the following CANNOT be true?
Marissa-AvnaimMay 5, 2020
Question
Can someone please explain the logic behind knowing to switch T and H and F and J? I skipped this specific question because I was not sure how to approach it. Thank you!
Reply
Create a free account to read and
take part in forum discussions.
This question assigns Q to the first group and S to the third group. This setup is consistent with the scenario we used for #8 (according to the numbering used in the video), so to save time, we use the same scenario to determine what can be true. Using this arrangement, we are able to eliminate answer choices A, B, and C, but we are left with D and E. Now, our task is to try to prove that one of these remaining answer choices could be true and can be eliminated. Answer choice E says "there is exactly one child in group 3." This condition is not met in the scenario we borrowed from #8, but we can achieve it by switching T and H with F and J. Switching these assignments meets all of the rules, keeps Q in 1 and S in 3, and creates a situation in which there is exactly one child in 3. With this, we prove that E is possible and can be eliminated. This narrows it down to D as the correct answer.
Does that make sense? Please let us know if you have any other questions!
