October 2010 LSAT Section 3 Question 11

Psychologists observing a shopping mall parking lot found that, on average, drivers spent 39 seconds leaving a parkin...

Grace-Luker on June 17, 2020

Large Sequencing

Hi! For question 15 and determining why E is the correct choice, why did you start 1961-1964 with K and J "respectively" instead of H and M? Does it matter which one you choose? In the problem, H and M ALSO come before O, also J and K have no relationship to O, so I'm confused as to why those would come first. Couldn't both sets of letters come first?

Create a free account to read and take part in forum discussions.

Already have an account? log in

Skylar on June 17, 2020

@Grace-Luker, happy to help!

K and J must be placed in the first two spots in Question #15. This is because the question tells us that J joined in 1962, so we assign him to the second spot. Rule #2 says that K must join before J. Since J is 2nd, this means that K must be 1st. Therefore, the earliest that H can be is 3rd.

Let's look at (E). Is it possible to place O fourth? Although O does not have a specific relationship with K and J, we know from Rules #1 and #4 that both H and N must precede O. Placing these three partners as early as possible, H would be 3rd, N would be 4th, and O would be 5th. So, it is impossible for O to be fourth.

Does that make sense? Hope it helps! Please let us know if you have any other questions!