P: not A → not BP: B–most–YC: ?

Erap72400 September 5, 2022

How to I begin to diagram this question.

I framed out the premises with their contrapositives P1. /A>/B C. B>A P2. B-most-Y c. /Y-most-/B I got lost on how those are put together to find the conclusion.

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Emil-Kunkin September 6, 2022

Hi Erap,

In this kind of drill, I would try to link the two statements by seeing what they have in common, which is B in this case.

We know that all Bs are A, and that most Bs are Y.

Since we know that all Bs are also A, and that there are a lot of BYs, there must be at least one Y that is also A.