I do understand how if a premise includes most how the conclusion would then include some. I am struggling with that type of wording in the daily drill questions.
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@lauryndurham so "most" statements are reversible, but when you reverse them, "most" becomes "some."
What these two premises have in common is "A" but we need the contrapositive of P2 to get A in our S & N statement, since it is "not A" currently.
Contrapositive of P2 is:
A ==> B
Now to combine with our Quantifier, we need to reverse our "most" statement as follows:
X-some-A
Now we can combine these two premises:
X-some-A ==> B
To conclude:
X-some-B B-some-X
Hope that helps! For a more in-depth discussion of these concepts, please watch our video lesson on Quantifiers.
CrystalOctober 20, 2021
So most statements are reversible but some statements are not?
RaviFebruary 5, 2022
If you reverse a most statement, you must turn it into a some statement.
Most people in California are Rams fans
California-most->Rams fans
We can reverse that and turn that most statement into a some statement to also say
Some Rams fans are in California
Rams fans--some--California
Some statements are reversible in the sense that it doesn't matter which term is on the left or right side with the some statement we just wrote above (Rams fans--some--California), we could have also written it as
California--some--Rams fans
RaviFebruary 5, 2022
If you reverse a most statement, you must turn it into a some statement.
Most people in California are Rams fans
California-most->Rams fans
We can reverse that and turn that most statement into a some statement to also say
Some Rams fans are in California
Rams fans--some--California
Some statements are reversible in the sense that it doesn't matter which term is on the left or right side with the some statement we just wrote above (Rams fans--some--California), we could have also written it as
California--some--Rams fans
October 11, 2024
Can you explain how you got the conclusion from x-some-a==> B?
Emil-KunkinOctober 21, 2024
If we know that some Xs are also A, and we know that all As are B, we therefore know that the xs that are As are also Be
