If the city of Nomo is in country X, and if Hannah spends as many days as possible in Nomo and as few days as possibl...

Ravi August 22, 2019

@Meredith,

Let's look at (E) and (B).

In looking at the rules, we know that Hannah goes to 6 cities over 14
days and has to spend at least 2 days in each city. If she wants to
maximize her time in Nomo, this means she can spend up to 4 days
there, with the other 5 cities collectively taking up 10 days. These 5
cities can be distributed among X, Y, and Z in any manner as long as
each country has at least one city. This is why (B) is correct. It has
to be true that Hannah has the ability to visit 4 cities in Y, and she
can do this by going to 1 city in each of X and Z. (E) is out because
Hannah could visit 5 cities in Y and Z as long as she doesn't visit
any cities in X in addition to Nomo.

Does that make sense? Let us know if you have any other questions!

erica-scott August 21, 2020

I don't understand why she can't visit another city in X as long as she still spends her 4 days in Nomo. It is just one city in a country but not necessarily the only one?

frederickliu January 24, 2023

Why is E wrong given the possible set up of NOMO4 X2 Y2 Z2 Z2 Z2 -> which Hannah can visit at most 4 cities outside of X.
(X2 means Hannah spends 2 days in a city of X and NOMO4 is = X4)

frederickliu January 24, 2023

But couldn't (B) be out given the possibility of (E)? I don't understand your logic of explanation here. @Ravi.

If you can elaborate more that will be awesome. Thanks!

Emil-Kunkin January 25, 2023

Hi, E simply is not true. The question asks what must be true, and E, which is that she can only go to four in country X and Y, is not true. She could go to five in those two countries, so it does not have to be true she can only go to four.