As it is presented in the passage, the approach to history taken by mainstream U.S. historians of the late nineteenth...

LisaEaster on November 15, 2017

I am very confused on question 5. I think the explanation given is good when you already understand but not when you are first applying. I need this re-explained.

Marie on November 17, 2018

I have question about 14 and 15...
if question 14 says W arrives before R
Surely that condition is only valid for question 14 and not necessarily for question 15.
I know i am probably missing something obvious because I know that is one possible sequence that would be valid for all the questions but I kinda feel like the way its explained its become the only possible sequence...
could you clarify please

Ravi on December 21, 2018

@Franco,

Rule 3 tells us that if J is in 1, then H is in 2

J1 - ->H2

/H2 - >/J1

We're given H is in 2, but we can't assume that since H is in 2 that J is in 1. Why? We've already satisfied the necessary condition for the rule. in conditional statements, if you either 1) satisfy the necessary condition or 2) fail the sufficient condition, then the rule falls away. This is why J can go in 4, making C the correct answer.

@LisaEaster,

Happy to review #5 for you.

We're given two new rules: Hall views the site on the day after the day Knight views the site and Fennelly views the site on the day after Lopez views the site.

KH

and LF

We already know that Gupta comes after Hall, so we can make a box with KHG to combine these rules together. We also know that F has to go in 3 or 5. However, if we put F into 5, then L must go in 4, but L can't go into 4 because L can't go into either 4 or 6. Therefore, we know that F must go in 3, which means L must go in 2.

For the KHG box, we know that K can't go in 4 now because it if did, then L would have to be in 5. The only spot big enough on the board to accommodate our KHG box is the space from 5 though 7, so we have to put KHG in 5, 6, and 7, respectively.

Now, we only have two more pieces to put on the board: J and M, and we have two spots open: 1 and 4. If we put J in 1, then H must go in 2, but it can't since L is already there. Therefore, J must go into 4, and M must go into 1. The question asks us where J must go, and we know it must go in 4. Therefore, the answer is D.

@Marie,

Question 14 gives us an additional rule to answer this question. This additional rule limits the number of possible game boards becuase all game boards that apply to question 14 also have to satisfy this rule.

While this condition must be applied to question 14, it does not need to apply for other game boards and other questions. However, the work we did in 14 is highly valuable because it provided us with 4 distinct game boards that are subsets of all of the possible game boards that exist for this particular game.

You're right—for question 15, we do not have to limit ourselves to only looking at game boards in which W is before R. However, this question asks for a must be true, and if it is a must be true question, then it must be true across all types of game boards for this logic game. Since question 14's game boards are subsets of all of the possible types of game boards we can make for this game, we can use them to eliminate answers because if something isn't true in any one of those particular game boards, then it doesn't have to be true.

Question 15 falls into our lap because we can eliminate the four wrong answers using the work we did on question 14. You could eliminate the answers by using brute force and trying all of the answers out, but that would be a waste of time since we've already created game boards that allow get to the correct answer.

Does this make sense? Let us know if you have more questions!

Lani on September 10, 2020

I don't see a reply from the LSATMax team concerning the confusion for question 4. I see that some people asked to explain why the answer is C and not B according to the rules. So can someone please explain why C is the answer?

Lani on October 1, 2020

Where can I access all the full length LSAT test included in the course?

Lani on October 1, 2020

Where can I access all the full length LSAT test included in the course?