October 2010 LSAT
Section 1
Question 27
As it is presented in the passage, the approach to history taken by mainstream U.S. historians of the late nineteenth...
Replies
Mehran on March 14, 2018
That would be incorrect because L being last is your necessary condition.M3 ==> L6
not L6 ==> not M3
Remember, DON'T JUST REVERSE!
The existence of the necessary condition tells you nothing.
Hope that helps! Please let us know if you have any other questions.
zachmorley2 on June 15, 2020
LO must precede N, however, and it appears in the case of the second "LO" option on option C there would be no room for N.Jack on September 9, 2020
Im not sure if were referring to the same problem but I think we are (16m:12s of the video).I had this same question but I realize now why we can eliminate it answer choice C to question 7 on the first set of walkthrough problems. When placing G in the fourth position in the hypothetical, P can either go to 1 or 7, IF it goes to 7, then we can apply the first and second rule to know that LO cannot go 56, but its important to consider that P can also go to 1, which would not completely determine where O would go, we would be left with position 3 and position 6 as possibilities, which is why answer choice C does not sufficiently restrict/determine O
DiegoC on October 20, 2021
Are you sure? that you are teaching us the correct things because that doesn't make logical senseDiegoC on October 20, 2021
and is contradicts rule #2, so you guys are wrong.Ravi on February 6, 2022
@username, with C, just because M in third makes L go last does not mean that L in last makes M go third, so we can get rid of it.If L is sixth, Z cannot go first. With A, saying something has to go before Z is a convoluted way of saying Z can't go first, so that's our correct answer choice.