October 2010 LSAT Section 4 Question 20
If Juarez's session is on the 3rd, then which one of the following could be true?
3 Replies

Anita on May 6, 2018
The way I set this up was:_ _ _ _ _ _ _
FGHJKLM
1. H_+_M / M_+_H
2. M-J
3. L-F-(GK)
4. L NOT 2
First, I placed J and then G. Knowing G is attached to K, I placed K. I know M has to be before J, so I tried putting that in 2. Then, I had to figure out where L and F go before GK, so I put L in one and F right before GK. The last slot fits H, which is over 2 away from M, so that works. Does this help?
L M J F G K H
__ __ __ __ __ __ __
Esther on June 26, 2018
Why is A incorrect?
Anita on June 27, 2018
Let's try A. If we place M first:M - J - - - -
We've satisfied 2. We know L cannot be 2, so all of L-F-(GK) has to fit after J.
M - J L F G K
Then the only thing we have left is H for 2, but H, per rule 1, cannot be that close to M. So it can't work.