@Jaimee-Salgado if W is shown immediately before R, the following scenario would result:
WR > S
This is entirely based on the condition set forth in the question stem (i.e. WR) and rule 3 (R > S).
This means that the WT block is not possible, which invokes the contrapositive of rule 4.
This allows us to deduce that T > W (i.e. Waterloo is not shown earlier than Terry).
So we now have the following chain:
T > WR > S
We know T has to be on the half hour but with 3 shows behind it (i.e. W R and S), 2:30 and 3:30 are eliminated as possibilities, which means that T would have to appear in 1:30:
1 T 2 W R 3 S (note: S could also be at 3:30 instead of 3)
But we have nowhere to place GG, so (B) cannot be true.
Hope that helps! Please let us know if you have any other questions.
nonameMay 3, 2021
Why are the video explanations for this game on YouTube but not the LSATMAX app itself?
It seems like this could be an easy fix so it is very hard to understand why it is the case. Could there please be more explanations provided to the PT's?
