Replies

Ravi May 17, 2019
@RyanCamp,Happy to help.
The problem with (C) is that if we put G 4th, then P can go in 1 or 7.
This means that LO can go in 2 and 3 or 5 and 6, so O's position is
not completely determined if G is put in 4th. This is why (C) is
incorrect.
Does that make sense? Let us know if you have any other questions!
LSATChris September 27, 2019
This makes sense but what you said should be commented on. Since during testing I would run both models to assume correctness.