September 2017 LSAT Section 2 Question 22

# If George presents only on jitsuaku, then which one of the following could be true?

3 Replies

Ravi on June 2, 2019

@DDL,(C) is actually the correct answer choice, not (D).

If you have any questions on (C), let us know, and we'll be happy to help.

Sidrah on August 28, 2019

How is C the correct answer?Ravi on August 28, 2019

@Sidra,Let's take a look at (C).

If G is only in the J group, then we just need to figure out what can

happen with R and W. Based on our first rule, R has to be in J. R and

W can't both be in M and they can't both be in S. However, at least

one person has to go in the M group and at least one has to go in the

S group. Thus, we can break this up into different scenarios based on

who can be in the M group.

For the first scenario, is R is in the M group, then W can't be. This

makes M done. Because R is in M, R would also be in S in this

scenario. S can't have W then, so S is done. This means that W has to

go in J.

For scenario 2, if W is in the M group, then R can't be, so M is done.

Because W is in M, then W would also be in S. S can't have R, so this

makes S done. This means that R has to go in J. W could also go into

J, but she doesn't have to.

Looking at (C), we see that it's possible for (C) to occur in scenario 1.

We could have R in M, J, and S, G in J only, and W in J only.

Does this make sense? Let us know if you have any other questions!