September 2009 LSAT Section 4 Question 12

September 2009 LSAT Section 4 Question 12

1 Reply

Ravi on August 8 at 05:40PM

@Julie-V,Great question.

Looking at the rules, we can combine them to make a chain:

/L - >R - >M - >T - >/F

/L - >R - >M - >T - >/V - >S

The question asks us which pair contains at least one member who must

be in. This question, and others like it, are asking us to find

'either/or' relationships, and these are often revealed in the

conditional chains that we make from the rules.

Looking at our big chain, we see that L and R are in an either/or

relationship (/L - >R). If L is out, then R must be in, and if R is

out, then L must be in. Likewise, L and M, L and T, L and S, and V and

S are in either/or relationships. The correct answer choice will be

one of these pairs.

Looking at the answer choices, we see (B) says that L and M are a pair

where at least one of them must be in. As seen in our chain, this is

true, so (B) is the correct answer choice.

Generally, this strategy will work really well for this type of

question when you encounter it in the future.

Does that make sense? Let us know if you have any other questions!