LSATMax and COVID-19:
Amid these difficult times, we're lowering the price on all courses.
Free LSAT Practice
LSAT Practice Test
LSAT Practice Test Videos
eBook: The Road to 180
Law School Top 100
LSAT Test Proctor
LSAT Logic Games
Apple App Store
Digital LSAT Simulator
Fee Waiver Scholarship
LSAT Test Dates
LSAT Message Board
October 1996 LSAT
If R is not reduced, which one of the following must be true?
on July 31, 2019
Why not B?
Why is the correct answer not B?
on August 1, 2019
Let's take a look at (B) and (A).
If R is not reduced, then we know that L and M must both be reduced.
If L is reduced, then we know that P is not reduced. This means that P
and R occupy 2 of the 3 "not reduced" slots.
Recall the rule that states if N is reduced, neither R nor S is
reduced. We know that R isn't reduced, so the necessary condition for
that part of the rule is satisfied. However, look at the rest of the
rule. If N is reduced, then S can't be reduced. Conversely, if S is
reduced, then N can't be reduced. This means that either N or S can't
From this, we know that both W and G must be reduced.
(A) says G is reduced, and we know that must be true, so it's the
correct answer choice.
(B) says that N is not reduced. It's possible that N is reduced,
however. We just know that either N or S is not reduced, but it's
possible that N is the one that's reduced and S isn't reduced, so we
can get rid of (B).
Does this make sense? Let us know if you have any other questions!
Posting to the forum is only allowed for members with active accounts.