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Ravi August 8, 2019
@ishadoshi,For question 14, K doesn't have to go immediately before J.
Recall the chain we built using the rules
H - N - O
K - J - M
N - G - I
J - G - I
Notice that G has 4 people before it (H, N, K, and J), so there's no
way that G can go in 1964. It's possible that the order before G is H,
K, N, and J, so K doesn't have to go right before J here.
For question 15, we're told that J joined in 1962. Looking at our
chain, we know that J has K before it. Since there's only one spot
before J since J is in 1962, then this means K must be in 1961 and go
first. Here, K must go right before J. We know that (E) cannot be true
because O has 2 people before it (H and N), and there are already 2
people on the board (K and J), so the earliest O could go is 1965.
Thus, (E) is the correct answer choice.
Does that make sense? Let us know if you have any questions!