December 2017 LSAT
Section 4
Question 3
Any of the following could be true EXCEPT:
Reply
Irina on August 21, 2019
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Let's look at the setup for this game.
A travel agent is arranging a tour visiting exactly 4 of the 6 cities - H, J, M, O, S, T.
Each city will be visited only once.
___ ___ ___ ___
1 2 3 4
The tour's schedule is subject to the following constraints:
(1) H & T must be included in the tour but they cannot be visited consecutively.
~ HT
~TH
(2) If O is included, S cannot be.
O -> ~S
S -> ~O
This rule tells us that only one of the cities could be included either O or S, not both. Both could be excluded though.
(3) If J is included, it must be #3
J -> 3
(4) If both J & M are included, they must be visited consequently
J & M -> JM v MJ
Combined with rule (3) and rule (1), we can infer that if JM are included, J must be #3, and M must be #2, otherwise, T & H will be consecutive in violation of rule (1):
/H /H
/T /T
___ M J ___
1 2 3 4
We can also infer any scenario when J is included and is #3 per rule (3), H or T must be #4, otherwise, they would be consecutive in violation of rule (1).
Let's look at the answer choices:
(A) J is visited immediately after H is visited
O/S H J T
1 2 3 4
This is a valid order, thus (A) is incorrect.
(B) M is visited some time after J is visited.
We can tell right away by looking at our initial setup that if J is visited, #4 must be H or T, thus, it is impossible for M to be #4. Thus, this is the correct answer choice.
(C) O is included in the tour but visited third.
O H J T
1 2 3 4
This is one of the valid scenarios, thus (C) is incorrect.
(D) M is the only city visited between H & T.
O H M T
1 2 3 4
This is one of the valid scenarios, thus (D) is incorrect.
(E) More than one city is visited between H & T.
H M J T
1 2 3 4
This is one of the valid scenarios, thus (E) is incorrect.
Does this make sense?
Let me know if you have any further questions.