December 2017 LSAT
Section 4
Question 3

# Any of the following could be true EXCEPT:

Reply

Irina on August 21, 2019

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Let's look at the setup for this game.

A travel agent is arranging a tour visiting exactly 4 of the 6 cities - H, J, M, O, S, T.

Each city will be visited only once.

___ ___ ___ ___

1 2 3 4

The tour's schedule is subject to the following constraints:

(1) H & T must be included in the tour but they cannot be visited consecutively.

~ HT

~TH

(2) If O is included, S cannot be.

O -> ~S

S -> ~O

This rule tells us that only one of the cities could be included either O or S, not both. Both could be excluded though.

(3) If J is included, it must be #3

J -> 3

(4) If both J & M are included, they must be visited consequently

J & M -> JM v MJ

Combined with rule (3) and rule (1), we can infer that if JM are included, J must be #3, and M must be #2, otherwise, T & H will be consecutive in violation of rule (1):

/H /H

/T /T

___ M J ___

1 2 3 4

We can also infer any scenario when J is included and is #3 per rule (3), H or T must be #4, otherwise, they would be consecutive in violation of rule (1).

Let's look at the answer choices:

(A) J is visited immediately after H is visited

O/S H J T

1 2 3 4

This is a valid order, thus (A) is incorrect.

(B) M is visited some time after J is visited.

We can tell right away by looking at our initial setup that if J is visited, #4 must be H or T, thus, it is impossible for M to be #4. Thus, this is the correct answer choice.

(C) O is included in the tour but visited third.

O H J T

1 2 3 4

This is one of the valid scenarios, thus (C) is incorrect.

(D) M is the only city visited between H & T.

O H M T

1 2 3 4

This is one of the valid scenarios, thus (D) is incorrect.

(E) More than one city is visited between H & T.

H M J T

1 2 3 4

This is one of the valid scenarios, thus (E) is incorrect.

Does this make sense?

Let me know if you have any further questions.