All the apartments on 20th Avenue are in old houses. However, there are twice as many apartments on 20th Avenue as th...

@chris_va on September 2, 2019


By saying most contain more than one isn't that vague enough to negate the possible flaw. The correct answer choice could very well work with the existing argument. I guess it just would have seemed more like a flaw if the conclusion said all houses have more than one.

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shunhe on December 21, 2019


It's true that the correct answer choice could work with the existing argument, but what matters here is the fact that the correct answer choice could also prove the existing argument wrong. Assume, for example, that 2 houses each have 10 apartments and 8 houses have 0 apartments. Hope this helps.