December 2009 LSAT Section 2 Question 10

December 2009 LSAT Section 2 Question 10

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Irina on September 20, 2019

@Meredith,The question asks us which of the following would have the same effect as the condition that H must be hung before K but cannot be the first.

For a substitution question, let's see what effect does the original condition have first.

The game requires us to determine the order of 7 photographs - F G H I K L M.

The following rules apply:

(1) G must be immediately before K

GK

(2) H must be somewhere before K but cannot be first.

This rule tells us that the lowest placement for H could be #2 and in combination with rule (1), we can infer that the lowest placement for GK could be #3 and #4 respectively. The highest placement could be #5 because GK must come after it. So H could be in spots -#2, #3, #4 or #5.

(3) I & L must be next to each other:

IL

(4) M must be #1,#2, #3

(5) F must be #1 or #7.

Let's look at (E):

K is somewhere after H, which must be somewhere after F.

The first part parallels the original rule but the second part is not the same because F could be #1 or #7, so this rule would, in fact, contradict the F- 1 v 7 rule because it is impossible for H to be after F if F is #7. Since this rule contradicts one of the other rules, we can conclude that (E) is incorrect.

Let me know if you have any further questions.

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