Which one of the following partners cannot have the third highest salary?

Irina on October 25 at 06:05PM

@Reina,

Thank you for your question. Could you clarify which game you are referring to?
The game that appears attached to this question is a law firm partners game.

Reina on October 29 at 01:35AM

Yes this is the December 2000 game from the sequencing games section

Irina on November 4 at 05:53PM

@Reina,


Thanks. The game requires us to rank 7 TV programs - H J L P Q S V.
The following rules apply:
(1) J & L are each less popular than H.
H> J
H >L

(2) J is more popular than Q
H > J >Q

(3) S & V are each less popular than L
H > L >S
H > L> V

(4) P &S are each less popular than Q
H> J> Q > P
H> J> Q> S

(5) S is not 7th

__ __ __ __ __ __ __
~S

Taken together we have the following chains:
H> J> Q > P
H> J> Q> S
H > L >S
H > L> V

The reason answer choice (E) in question 1 is incorrect because it violates rule (5) - S cannot be #7,

The correct answer to #5 is (B). Question 5 asks us if Q is more popular than L than each of the following must be true EXCEPT:. Let's add this rule to our original diagram:

H > J > Q > P
L> S
V

We can infer that H must be #1, J -#2, Q -#3 - thus we can eliminate (A), (D) and (E). We can also infer that either L or P must be fourth because S and V must go after L per rule (3). Since the highest rank L could take is #4, it is not possible for either S or V to be fourth, thus we can eliminate (C) - remember, it is an EXCEPT question. The correct answer is, therefore (B) since L could be but not must be fourth as P could be fourth instead.

Let me know if this makes sense or if you have any further questions.

Reina on November 5 at 01:57AM

Thank you!