October 2010 LSAT Section 4 Question 20

# If Juarez's session is on the 3rd, then which one of the following could be true?

2 Replies

Irina on November 6 at 05:52AM

@tomgbean,This order is fine generally but this question asks us which of the following could be true if J is 3d, whereas your hypothetical has J on the second, thus it is inapplicable to this question. If J is #3, M must be #1 or #2 since M must be on an earlier day than J. We know that H must be after J since at least 2 sessions must separate M and H, thus we only have three open spots left after J (one is occupied by H), meaning FGK must go in these spots. Since L must go before F and it cannot be #2, L has to be #1 in this scenario, which means M must have session #2. F must be #4 since GK must go after F, and H cannot be in #4 because at least two sessions must separate M and H. GK must go together and could either be #5 and #6, and H would be #7 in this scenario. Or alternatively, H could be #5, and GK #6 and 7. These inferences allow us to conclude that if J is #3, only two scenarios are possible:

(1) LMJFHGK

(2) LMJFGKH

We can thus conclude that only (D) could be true, (A) must be false since M must be #2 if J is #3.

Let me know if this makes sense and if you have any other questions.

on November 7 at 03:38AM

Thanks. Missed that. Will read carefully in the future.