October 2010 LSAT
Section 1
Question 27

October 2010 LSAT
Section 1
Question 27

Reply

Irina on November 20, 2019

@devinkramer,Thank you for your question - you are correct, it is a mistake in the explanation. There are four possible combinations though so (A) is still the correct answer choice.

If W arrives before R, we know that Y has to be #4 because if W is #4, R must arrive #5 and is followed by V/T as #6 and #7 but we cannot have VT or TV per the rules, hence W cannot be #4.

__ __ __ Y __ __ __

S arrives before Y and after W - W > S > Y so W cannot be #3. Since we know that T & V must follow R, R cannot be #5 or it will result in TV/ VT combination, thus R must be either #2 or #3, and W must be #1:

W>R/S>S/R>Y> T/V> Q>V/T

We can conclude that overall there are four possible combinations under this scenario:

W R S Y T Q V

W R S Y V Q T

W S R Y V Q T

W S R Y T Q V

Let me know if you have any other questions.

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