September 2018 LSAT
Section 4
Question 22
Which one of the following pairs is an artist and musician who CANNOT be scheduled for the same week as each other?
Reply
Irina on November 27, 2019
@klellhenness,Happy to help. The game requires us to determine the order of five exhibitions - J K L N O and five performances - T V W Y Z.
A: __ __ __ __ __
M: __ __ __ __ __
1 2 3 4 5
The following rules apply:
(1) J exhibit is earlier than K, and K is earlier than L.
This rule tells us we have the following chain: J - K - L. We can thus infer that J cannot be #5 or #4, K cannot be #5 or #1, and L cannot be #1 or #2.
(2) T performs earlier than V, who performs earlier than W.
This rule tells us we have the following musician chain - T - V- W. We can infer that T cannot be #4 or #5, V cannot be #1 or #5, and W cannot be #1 or #2.
(3) W does not perform in the 4th week.
A: __ __ __ __ __
~K ~L ~J ~J
~L ~K
M: __ __ __ __ __
~W ~W ~W ~T
~V ~T ~V
We can infer that W can only perform in weeks 3 or 5
A: __ __ __ __ __
~K ~L ~J ~J
~L ~K
M: __ __ __ __ __
/W /W
~V ~T ~V
~T
which means we have two possible scenarios for the order of musicians:
1. W performs 3d
This scenario allows us to conclude that T must perform 1st, and V second, and Y/Z could be 4th or 5th in either order.
T V W Y/Z
2. W performs 5th
This scenario allows for any order of T V Y Z as long as T is before V.
(4) Y does not perform at the N exhibition.
Y =/ N
(5) Z performs at the O exhibition.
Z=O
The question asks us which of the following pairs is an artist and a musician who cannot be scheduled for the same week as each other?
Since we have two chains - J - K -L and T -V - W but only five slots, it is not possible for L & T to overlap and still leave space for Z and O pair:
J K L _ _ <- no space for Z & O
_ _T V W
This, we can conclude that L & T cannot be scheduled for the same week (C)
Let me know if this makes sense and if you have any other questions.