September 2018 LSAT Section 4 Question 4

# Which one of the following pairs is an artist and musician who CANNOT be scheduled for the same week as each other?

1 Reply

Irina on November 27, 2019

@klellhenness,Happy to help. The game requires us to determine the order of five exhibitions - J K L N O and five performances - T V W Y Z.

A: __ __ __ __ __

M: __ __ __ __ __

1 2 3 4 5

The following rules apply:

(1) J exhibit is earlier than K, and K is earlier than L.

This rule tells us we have the following chain: J - K - L. We can thus infer that J cannot be #5 or #4, K cannot be #5 or #1, and L cannot be #1 or #2.

(2) T performs earlier than V, who performs earlier than W.

This rule tells us we have the following musician chain - T - V- W. We can infer that T cannot be #4 or #5, V cannot be #1 or #5, and W cannot be #1 or #2.

(3) W does not perform in the 4th week.

A: __ __ __ __ __

~K ~L ~J ~J

~L ~K

M: __ __ __ __ __

~W ~W ~W ~T

~V ~T ~V

We can infer that W can only perform in weeks 3 or 5

A: __ __ __ __ __

~K ~L ~J ~J

~L ~K

M: __ __ __ __ __

/W /W

~V ~T ~V

~T

which means we have two possible scenarios for the order of musicians:

1. W performs 3d

This scenario allows us to conclude that T must perform 1st, and V second, and Y/Z could be 4th or 5th in either order.

T V W Y/Z

2. W performs 5th

This scenario allows for any order of T V Y Z as long as T is before V.

(4) Y does not perform at the N exhibition.

Y =/ N

(5) Z performs at the O exhibition.

Z=O

The question asks us which of the following pairs is an artist and a musician who cannot be scheduled for the same week as each other?

Since we have two chains - J - K -L and T -V - W but only five slots, it is not possible for L & T to overlap and still leave space for Z and O pair:

J K L _ _ <- no space for Z & O

_ _T V W

This, we can conclude that L & T cannot be scheduled for the same week (C)

Let me know if this makes sense and if you have any other questions.