If orange glass is used in more of the windows than green glass, then the complete color combination of the glass in ...

Isaak on December 20 at 05:43PM

Why doesn't answer choice D work? I can't seem to figure that out

I placed Y,P, and R within window 1, G,P,O, and R within window 2, and O and G in window 3

3 Replies

Ben on December 20 at 06:01PM

Hi ielkind, thanks for the question.

This is a tough game, so I understand your difficulty here.

It's important to keep in mind the strict numerical restriction this question forces upon us. In this case, it says more O than G. Meaning immediately it is either two or three Os are placed within the three windows.

Since, O and Y cannot be placed together, yet Y must be placed somewhere. This means that O will be restricted from at least one window. As a result, we can have O a maximum of twice.

If we have more O than G, then G can only be placed once. (I notice this is the mistake in the description of your setup. You have G placed twice).

Window 1: Y, P, R
Window 2: G, P, O, R
Window 3: P, O

This way we have more O (two) than G (one). P and O can be a complete window.

I hope this helps. Please let me know if you have any other questions.

on December 26 at 07:05PM

I'm confused about the last rule. If not P -> O with the contrapositive of not O -> P. I took this rule as one window either has to have O OR P and cannot have both. Can you please clarify how this rule works so that one window can have both P and O. Thanks!

Skylar on January 5 at 11:39PM

@mamie, happy to help.

Your diagram of the last rule is correct. We have:
NOT P -> O
NOT O -> P

However, your interpretation of this diagram seems to be where you're getting confused. We know that if there is no P in a window, we must add O. We also know that if there is no O, we must add P. However, we know nothing if P is the Sufficient condition or if O is the Sufficient condition, meaning we have no deductions to make if we are first told that the window has P or if the window has O.

So, this diagram means that each window must have at least one of O or P, and could possibly have both. This can be remembered as "at least one is in."

Does that make sense? Please let us know if you have any other questions and best of luck with your studies!