We are told that O is selected for the first Sunday.
Rule #4 states: J and O -> J - O. The contrapositive of this is: O - J -> NOT J or NOT O. Basically, this means that if both J and O are selected, J must precede O. If O would precede J, then they cannot both be selected. In this scenario, we know O is selected and is in spot 1, which means it would be impossible for J to be earlier than O. Therefore, J cannot be selected in this scenario.
The game setup tells us that exactly two of Giuliani's three concertos will be selected. Since we just eliminated J as an option, this means that the remaining two of Giuliani's concertos - H and K - must be selected. So, we can accurately say that K must be selected if O is selected for the first Sunday.
Does that make sense? Please let us know if you have any other questions and best of luck with your studies!
yckim2180on June 8, 2021
Why is N also not the right answer since we also need two of R's concertos?
balde_kadija@yahoo.comon July 26, 2023
I don't understand how it's possible to have O without having J. Rule #2 states M -> NOT J & NOT O, correct? With this being an in/out game, I took that to mean that J and O must always be together, whether they are both in or both out...the reason being that if M is chosen then J nor O can be chosen AND if M is not chosen then J and O must be chosen in order to avoid either J or O being in the same category as M. Can someone please explain to me what I'm missing?
Emil-Kunkinon July 30, 2023
The rule is that if M is in J and O must be out. This tells us nothing about what happens if m is out. It's possible that if m is out then both j and o are in, that only one is in and the other is out, and that they're both out. J and O are not a block, there's no issue with M being together with either J or O in the out category, only with them being together in the in category.
