June 2019 LSAT Section 4 Question 22

# If Morse works on Thursday, which one of the following must be true?

2 Replies

Alexander on February 9 at 04:24PM

Annndddddd I figured it out on permutation 22... Nevermind. I see what information I needed. Still, I feel like it took me forever to work out.Irina on February 12 at 11:42PM

@Alexander-Blankers,

The quickest way to approach this question is to refer to the initial setup instead of trying different scenarios. We have 5 volunteers L M N P Q and 9 open slots to fill. No volunteer can work on all three days, which means we have 4 volunteers working 2 days and 1 working 1 day:

2-2-2-2-1

Since M & L always go together, L must definitely volunteer 2 days though M could volunteer one.

L-2-2-2-1

This specific question asks if M works on Th, which of the following must be true. Well, we know that if M works on Th, then L works on Th as well. Where can the second L go?

Th M L ___

F N ___ ___

S ___ ___ ___ ~P

There are two different options here - M works two days or M works one day. If M works two days, then the only day the second M & L pair could go is Sat.

It cannot go on F because then there is no space left for P & Q:

Th: M L P

F: N M L

S: Q ??

This scenario results in P & Q only volunteering for one day, which is impossible per our inference above. Hence we can conclude that M & L must go on S:

Th: M L P/Q

F: N P Q

S: M L Q /N

The second option is if M only volunteers for one day.

Th: M L P

F: N P Q

S: Q N L

In this scenario, every other volunteer must volunteer for two of the days. Since P cannot volunteer on S, we know that P must go on Th & F. The only remaining spots for Q are F & S. And the remaining volunteers N & L must go on Sat as well.

Just by looking at these two scenarios, we can see that the only condition that must be true is that Q works on Friday.

Let me know if this makes sense or if you have any other questions.