September 2018 LSAT Section 4 Question 18

# Which one of the following CANNOT be true?

4 Replies

Thomas on February 18, 2020

Sorry, correct answer is A, not B. Typo**Kaden on September 6 at 05:50PM

@ThomasThis is a CANNOT be true question. A and B are both possible options. C is the only option that is not possible.

A) If F has L,P, S then your left with M,R,Z for G and H. H has to have 2 but cant have M so it gets R and Z leaving G with M. This also satisfies the rule that if G has M it cannot have anything else. So this looks like the following and is valid:

F: L P S

G: M

H: R Z

B) This one is very similar to A. If L has L, R, and Z that leaves M, P, S for G and H. H needs 2 and cant have M, also P and S have to go together, so P and S go in H. And this leaves M for G. Again satisfying the rule that if G has M then it cannot have anything else. This looks like the following and is valid:

F: L R Z

G: M

H: P S

C) This one gives you P, S, R in G leaving you with L, Z, M for F and H. We know H needs two but also know one of L and Z must be in F from the first rule and M cannot be in H. This leaves us only the remaining of L and Z for H but it needs two so there is no valid scenario. This answer cannot be true and is the answer

Sabine on September 27 at 07:31AM

Why does H need two spots? Isn't one spot enough?H and F can have either L or Z, correct? Meanwhile, F can have M, L or Z.

Sabine on September 27 at 07:32AM

Nvm, I forgot one of the rules for H. Thanks