September 2019 LSAT
Section 1
Question 6

September 2019 LSAT
Section 1
Question 6

Reply

shunhe on February 25, 2020

Hi @annaj,Thanks for the question! Note first that if S is not displayed, there are three more puppies that can be picked. Now we can note that at most, 3 kittens can be used (because we canâ€™t have G and H from the 3rd rule), so picking only 1 more puppy isnâ€™t an option. If we pick the other three puppies, on the other hand, that means weâ€™ve picked W, which means we have to pick G (4th rule), which means that G is in the 2nd pen, which means that T canâ€™t be picked (since in this scenario, the 1st, 2nd, and 5th pens hold kittens from rule 1 and 4, and T canâ€™t be next to a kitten from rule 2). In other words, we have to pick two puppies: R and T/W. But thereâ€™s no way to display just R and T, since if we just have those two, we have three cats, and once, again, T will have to be next to a cat. So weâ€™re displaying R and W.

We know that W is displayed, and so G is in the second pen. This is what (C) tells us, and (C) is the correct answer.

Hope this helps! Feel free to ask any other questions that you might have.

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