September 2018 LSAT
Section 4
Question 11

September 2018 LSAT
Section 4
Question 11

Reply

Ravi on March 3, 2020

@annaj,Happy to help. Let's take a look.

We're told H is going with one other person in a scenario. Since we

know H can't go in O, then this means that H can either go with one

other person in R or V.

Looking at if H goes with one other person in R, this closes R out and

also closes V out since R has to have more people than V. However, we

also know that GM have to go in either R or V since G can't go in O,

so this means there's no room for GM in this scenario. Thus, we know

that this scenario won't work, and this means that H will have to go

with one other person in V. Also, since G, M, F, and K won't be going

into V, this means that L will be the one person going with H in V.

With H and L in V, GM goes into R. Since there are 6 people, two are

already in V, R has to have more people than V, and each booth has to

have at least one person, this means that R will have exactly 3 people

total. F and K are the only two pieces left, and no rules surround

them pertaining to going into O or R, so they can switch between these

two booths.

Lookin at (A), we know this is false since L is in V. (B) looks great

though and could definitely be true, since F could be in either O or

R. Thus, (B) is the correct answer choice.

Does this make sense? Let us know if you have any other questions!

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