June 2019 LSAT Section 4 Question 15

The schedule of the paintings shown in the four weeks is completely determined if which one of the following is true?

Golnar-Roughani on May 12, 2020

Please explain the best strategy

I can't seem to tackle this one efficiently. I had all my deductions down and got the other questions right but when it came to this one I had to plug in every single answer choice which ate up a lot of time and I still got it wrong. I got answer choice D. Can you explain what's the best way to approach this question?

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zia305 on May 30, 2020

Can someone please explain the right answer?

Chase on July 3, 2020

Can somebody please explain how E is any different from answer B?

amh on August 1, 2020

E is different from B because if there's S there has to be an H with it, but if there's H there doesn't necessarily have to be an S with it.

Emil-Kunkin on April 27 at 02:14PM

If S is twice that means H is twice two. Since our Hs can't be back to back, that means one must be before three, so I must go in the first week. This also means that our two SH blocks must go in weeks two and four. So we have

I H _ H
_ S _ S

Since all of them must appear, we know that g must go in three, which forces p into 1, and r goes in the last remaining spot, three.

I would look to the answer choices that are most determinative first, and Placing S also places H, thus filling half the board already.