If W is in H we can then try to place our Tr block. If we try to put TR in G, this forces S into F, and if S is in F, then X is in G, but since we cannot have three things in G, this is impossible. Therefore we must instead put the TR block in F, giving us
F: T R G:_ _ H:_ W
We also know that since S can't go with W it must go in g.
Therefore the other four are possible, but s can't go in f since it's full.
