If corsage 1 contains at least one gardenia and at least one violet, and if corsage 3 contains three different types ...

Sylvie on July 3, 2020

Eliminating Incorrect Answer Choices

Hi, Can someone please explain how to whittle down answer choices here? I understand why B cannot be true (2 orchids), but I'm having trouble choosing between A, C, D, and E. I had the same problem with question 190 (question 4 in the game setup video), though I felt more confident about my answer choice there. Both questions are missing a question explanation video, and the answer review doesn't really go into detail on why an answer is right or wrong, so if somebody could weigh in to give me some clarity I'd really appreciate it!

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Sylvie on July 3, 2020

For clarification: the problem set in question appears to be drawn from the October 1992 LSAT (section 3, questions 4 and 7). I accessed them via the analytics tab by filtering for group games. Just wanted to be clear!

Sylvie on July 3, 2020

*** October 1993 ***

Apologies for the typo.

shunhe on July 5, 2020

Hi @Sylvie,

Thanks for the question! So you already eliminated (B) because it has two orchids, which is great. Now let’s take a look at why you can eliminate (C), (D), and (E). It’s actually the same thing that eliminates all three of those answer choices.

So we know that based on the hypothetical presented in this question stem, corsage 1 is going to have at least one G and one V. Well, recall from rule 1 that corsage 1 has exactly two types of flowers. That means that corsage 1 is going to have Gs and Vs only, no Os or Rs in Corsage 1. OK, well, also recall that the nine flowers used are going to include at least one flower from each of the four types—in other words, we need at least one G, V, R, and O in the final diagram. But we know that corsage 3 doesn’t have any Os. Well, if corsage 1 doesn’t have any Os, and corsage 3 doesn’t have any Os, then corsage 2 has to have an O (since an O has to appear somewhere). But (C), (D), and (E) are all answer choices that don’t have Os! Which means we can eliminate all three of them for that very reason. Then, we eliminate (B) because it has two orchids, and that leaves us with (A).

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Hope this helps! Feel free to ask any other questions that you might have.

Sylvie on July 5, 2020

Thanks @shunhe ! I clocked the min. 2 requirement for the first corsage but overlooked the fact that it was *exactly* 2. Appreciate you clearing that up!

shunhe on July 6, 2020

Glad you got it now! And yup, getting every detail is super important.