October 2015 LSAT
Section 3
Question 7

October 2015 LSAT
Section 3
Question 7

Reply

shunhe on August 5, 2020

Hi @Gabriela-Diaz,Thanks for the question! Yes, the rule is biconditional here. Generally speaking, when we talk about “equality,” like X = Y (so here, the number of H’s photographs in L must be the same as the number of F’s photos in S can also be expressed, H’s photographs in L must be equal to F’s photos in S), it’s biconditional. And how would it be possible for X to be the same as Y, but Y to not be the same as X? Or vice versa? It wouldn’t be. And so the rule cuts both ways.

Hope this helps! Feel free to ask any other questions that you might have.

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