June 1991 LSAT Section 4 Question 21

A society in which there are many crimes, such as thefts and murders, should not be called "lawless." That is an abus...

ankita96 on August 11, 2020

Ans Choice C and E

Hi, I read the explanation in the previous thread. I agree to what you are saying. However when doing quantifiers is it not true that many is represented as Some and a reversable statement. So shouldn't many here also mean that 'at least one'. Thanks in advance!

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ankita96 on August 11, 2020

*Reversible, sorry for the error!

shunhe on August 11, 2020

Hi @ankita96,

Thanks for the question! Your’e right in saying that “many” is represented as “some,” and that “some” is a reversible statement. So “many X are Y” can be expressed as “some X are Y,” which can be reversed to say that “some Y are X.”

However, that being said, the correct answer choice here is still (D) (and that’s actually in part the reasoning that makes (D) true). We’re basically told that a society with no laws would have no crimes. So that’s saying

~Laws —> ~Crimes

And of course the contrapositive

Crimes —> Laws

Which is reflected in (D). The reason that (E) is wrong is because in this stimulus, we’re drawing a distinction between “some” and “many,” or otherwise (D) and (E) would say the same thing. And in that distinction, “many” is going to be more than “some.” But we can only conclude “some,” and not “many.” So in this instance, “many” not only means “at least one,” but also “more than some.”

Hope this helps! Feel free to ask any other questions that you might have.

ankita96 on August 12, 2020

okay yeah that makes sense ... thank you!