Thanks for the question! So remember, we know that S is a labrador, exactly one labrador wins a ribbon. We also know that S places ahead of Q and T, and since S finishes ahead of two dogs and only two dogs don’t get ribbons, S has to get a ribbon. So S is a labrador who has to get a ribbon. And exactly one female dog gets a ribbon, so S is the female labrador that gets a ribbon. U is a labrador, and since only one labrador gets a ribbon, U doesn’t get a ribbon. So now U, Q, and T are behind S, and P and R are ahead of S. Well, that means that S is in third place, and P and R are in first and second place, though we don’t know which is which. But that means first and second are both greyhounds. So there can’t be a labrador in second place. And that’s how we can eliminate (B).
Hope this helps! Feel free to ask any other questions that you might have.
ankita96on August 24, 2020
Yes that makes sense, thanks!!
akinyiwilliamson December 24, 2020
So there is no scenario with Q and T in, where either P or R is out. Both P and T have to in the 4 with ribbons in any scenario, right?
