Thanks for the question! So we’re told that both Ms and Hs are in the forest. What must then result? Well, according to rule 1, G is not in the forest. And according to the contrapositive of rule 3, since G isn’t in, W isn’t in. Now, based on rule 4, we know that at least one of J and S are in. So now we need to know something that must be true, and that’s (E), that there are at most two other kinds of birds in the forest (J and S).
Hope this helps! Feel free to ask any other questions that you might have.
McLeanon June 15, 2021
Hi, I'm still a little confused on this question, the contrapositive of rule 3 states Not G --> Not W, but since we only know that we don't have G how can we invoke that necessary condition to mean that we don't have W as well? Wouldn't that be working backwards?
ScienceMathTutoron September 28, 2021
Shouldn't the question read "...that COULD be in the forest" as J&S are mutally exclusive?
