Thanks for the question! You can have four birds when you take out W and G. Because remember, if W is in, then H, J, and M can’t be in. So we need to take W out, so leaving W in knocks out three other birds. You also have to take G out, because when you put G in, H can’t be in, and that means M and J again can’t be in. So we take G and W out, and that means we leave J, H, M, and S in. No other rules are contradicted, so this is a valid group, making (C) the correct answer.
Hope this helps! Feel free to ask any other questions that you might have.
Clauzavalet1on March 12, 2021
How are J,H,M,S in? That would contradict the rule that "when J is out then S is in".
jrb970on April 1, 2021
No, the rule states that if J/S are out, then S/J are in. The rule does not state that both J and S can be in at the same time. Following the rule, you cannot have both S and J out at the same time.
Mallorion May 12, 2022
That still doesn't make sense to me. How can S and J be in the forest when the last rule states that it's (S or J)?
Emil-Kunkinon May 12, 2022
Hi,
The last rules tells us that if jays are not in the forest then shrikes are. We could diagram this as
If not J - S and If not S - J.
In other words, they cannot both NOT be in the forest (or in better words, at least one must be in), but we are not actually told that they cannot both be in together. The rule never tells us "but not both," which is how a rule would state that its either/or.
