December 2009 LSAT - Section 2 - Question 9
Emil-Kunkin January 6, 2024
For any scenario question, we should start with what must be true and here, we know that f must be one. So, we know then that we have five spots Left and two blocks of two. This leaves us with only two things that are impossible, h cannot go four or six, because that would necessarily break up one of our two blocks. So we don't even need to worry about restrictiveness