June 2011 LSAT Section 2 Question 23

If boxes 2, 3, and 4 all contain balls that are the same color as each other, then which one of the following must be...

EMS on June 23, 2021

Why D and not B?

If there have to be more R than W, and 2 of the balls are the same in 2,3, & 4 and 1 cannot be a R, then 2, 3, & 4 would be G. If there is W in 1 then there must be 2 R balls so 5 & 6 would be R and there would be exactly 3 G balls. Why would B be incorrect then?

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Victoria on June 23, 2021

Hi @EMS,

Happy to help!

Answer choice (B) is incorrect because it does not have to be true. There is at least one possible scenario where less than three of the boxes contain G balls.

G R R R W G
1 2 3 4 5 6

Notice that the above meets all of our conditions:

1) There are more R balls (3) than W balls (1)

2) There is a box containing a G ball (Box 1) that is lower in the stack than any box that contains an R ball (Boxes 2-4)

3) There is a W ball in a box (5) that is immediately below a box that contains a G ball (6)

4) Boxes 2, 3, and 4 all contain R balls

Hope this helps! Please let us know if you have any further questions.