Hi Connor, lets start out with the general setup of the game:
I would probably say this is a hybrid game, we have five in order, and there are two who are not in the order at all.
I would consider a setup like this
_ _ _ _ _ (_ _) With the parentheticals being the ones not selected.
From the rules, we know that L is in, and is 2 or 3, and that if G, g is 1. We also know who must be last, so
_ _ _ _ N/T (_ _)
We then have a few conditional rules:
If I and R -> RI
If O and R -> RO
If N and T -> NT
Putting the first two conditionals together, we see that they cannot both happen at the same time, so we know that we cannot have all three of I, O, and R selected.
Our final conditional tells us that if N and T, then
_ _ _ N T (_ _)
If I is 4, we know the following
_ _ _ I N/T (O/R N/T)
We know that both N and T cannot be in, since if they are both in, then N is 4. We also know that one of O or R must be out. Thus, G, I, and L must be in, so A is correct.
