We have three sessions, and we know the following about each of them.
W: More than FA, cannot have Q or P FM: Cannot Have S FA: Not T We also know that T>P.
Let's put M on Friday afternoon
W: _ _ FM: FA: M
We know that W must have more than Fa, so we know that W must have at least two. Since we also know that Q and P cannot go in W, the two remaining ones who can are T and S, so they must both go in W. Thus, A is correct.
