If corsage 2 is exactly the same as corsage 3, the nine flowers used in the corsages can include exactly

Emil-Kunkin on May 20 at 09:28PM

Hi, apologies! Let's take a look.

For this question, we know that 2 and 3 have at least one G and R each, and neither has an O, so there must be an O in 1

1: O _ _
2: G R _
3: G R _

We also know that we must have a violet somewhere, so either there are violets in 23 or in 1, or potentially in both. However we know that there are only four open sports so there cannot be five violets, so we can knock out E.

We can also knock out D, since 5 roses would require one more rose in each of 2 and 3, and then one rose in 1, which would mean that 1 would have R O R/O which would mean no violets.

For C we would have the following:
1: O R O
2: G R _
3: G R _

Which violates the rule that there must be twice as many Rs as there are Os, we we can knock out C.

For B, we would have the following:
1: O O G
2: G R V
3: G R V

Which violated the same rule as C.

We can try A, and we actually get a valid scenario

1: O O V
2: G R R
3: G R R