October 2010 LSAT Section 3 Question 11

Psychologists observing a shopping mall parking lot found that, on average, drivers spent 39 seconds leaving a parkin...

Aaronn on July 3, 2023

Question at 31:30

Hello, Would someone mind explaining in greater depth why A is possible? On the sequencing chart there is nothing to the left of Hodges, so how is A possible. I must be understanding the sequencing chart incorrectly. Any further and more in-depth explanation would be appreciated. Thank you, Aaron

Replies

Create a free account to read and take part in forum discussions.

Already have an account? log in

Emil-Kunkin on July 6, 2023

Hi, the chart just means that H doesn't HAVE to have anything before it. That doesn't mean that it's not allowed to have anything before it.

Aaronn on July 6, 2023

Hello,

Now I am confused. In other parts of the video the instructor counted the variables before the other and explained how certain variables could not fit into certain positions because in the sequence chain the variable had X other variables before it. By using the same logic, H would have nothing behind it no? If H does not have to have anything before it how do we know what does and how many variables are before a different one?

Emil-Kunkin on July 6, 2023

The sequence chain only shows what MUST but true. This shows that there isn't any variable that has to go before H, but there totally could be variables that do go before it, as long as they aren't after H on the chain. For A, K and J are both allowed to go before H. This would also be true of cases where there are variables that fall outside the chain. If there were a Z in this game, and Z was not part of the chain, Z could also go before H.