December 2003 LSAT
Section 1
Question 22
Emil-Kunkin on December 13 at 11:48PM
We know that m must review at least two plays, since m reviews more than l and k. However we also know m cannot be with j. This means that each of the three plays must have exactly one of j or m, otherwise we would not have more ms than k or l. In fact, we know there are two Ms and one J, so each of the three spots must have exactly one m or j. C is incorrect because it does not have one m or j. This would either force there to be only one m, zero js, or mj to be together, all of which violate rules.