June 2000 LSAT Section 1 Question 19

# Which one of the following could be a complete and accurate list of the members of the crew?

5 Replies

Melody on June 1, 2015

Make sure to note that the setup states that everything must be done in "at MOST three days." This means that we can have the partition built in two or three days (we know from the rules that T and P can't be on the same day so there are at least two days). Thus, we have two-day options and three-day options.Hope that clears things up! Please let us know if you have any other questions.

Amir on October 20, 2017

Hi Lsatmax!Why in writing the possibilities you come up with that one you wrote in 1-4; 3-2; 3-1-1; 2-2-1

I mean I understand the reason for numerical possibilities i.e. 4-1 or 3-2 or 2-2-1 or 3-1-1 but I don't understand why you wrote out each numerical with a particular assignment? As long as we keep P and T in separate groups we are good, aren't we? I couldn't understand why you put each variable in particular group? The explanation does not cover it. For example how come that in 4-1 numerical possibility you put FWS together with T and not P? the same goes for other numerical possibilities you wrote e.g. 2-2-1 or or 3-1-1? I see that you are using the possibilities you wrote in attacking the questions. So it seems that matters but an explanation is missing on how you reach that particular assignment of variables to each group. Please explain. Thanks!

Amir on October 20, 2017

Ooops! I figured out where I was wrong. I didn't read the scenario carefully where it says the actions are to be done in order. Thanks for the game and set up.on May 21 at 03:13AM

I am confused on this too. I see it says "at most three days" but also says "one task each day", so howcome there can be a day without any task?Victoria on June 6 at 02:18PM

Hi @navikaur,Happy to help!

The condition "at least one task is done each day" is referring to the days it takes to install the partition. While the crew has three days to install the partition, it is possible they could finish it in two.

The condition that tells us that at least one task must be done on each of the two days tells us that the crew cannot do all of the tasks on one day (reinforced by Rule 2) and that the crew cannot take three days to do the work but take one day off in the middle.

Overall, we know that the crew must install the partition in either two or three days. This condition tells us that the crew must complete at least one task on each day they are working on the partition. If the installation only takes two days, then there are no further tasks to be completed on the third day and it does not count as a day with no tasks because it is no longer part of the process of installation.

Hope this helps! Please let us know if you have any further questions.