October 1996 LSAT Section 3 Question 17

If on a nine–bead strand the first and fourth beads from me clasp are purple, and the second and fifth beads are yell...

David on October 23, 2015

The 8th bead could be Green

Understand the explanation but it could still be true that 7,8,9 were G,G,O and therefore B would also be correct. There are no rules that would prevent this instance so it could be true. Please explain.

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Melody on October 27, 2015

Don't forget rule # 4.

Because we have P in 1 and 4 and Y in 2 and 5, we must have R in 3 and 6 to fulfill rule #1. So that means we must have one G and one O in 7 and 8 to fulfill rule #4. Since rule # 3 tell us that R and O cannot be next to one another, O must be in 8 and that forces G to be in 7 (again because of rule #4). Then other than R, anything can be in 9 (R cannot be because of rule #3). Thus, we cannot have the 8th bead be G. It MUST BE O. If you re-watch the video for the question explanation, this is pointed out.

Hope that helps! Please let us know if you have any other questions.

David on October 27, 2015

Completely understand rule #4 and that anything could be in 9. Why can't O be in 9 and 7/8 be G? R and O are still separated and all colors are represented.

Andrew on September 13 at 10:27PM

This is my problem with the question as well. "O" could be in 9, it doesn't have to be green. Am I missing something?

Andrew on March 20 at 04:13PM

I just want to reiterate this question. I don't see anything wrong with B. PYRPYRGGO seems like perfectly plausible scenario to me and doesn't violate any rules

Andrew on March 20 at 04:15PM

Oh wait never mind. G&O beads have to be represented within the first 8. I interpreted this rule just to mean whenever there are 8 or more beads all must be represented