June 1993 LSAT Section 2 Question 4

# Scheduling Z's session for which one of the following days determines the day for which U's session must be scheduled?

6 Replies

Mehran on January 27, 2014

Thanks for your message. The video setup and video answer explanations for this game are now live inside of LSATMax.Hope this helps! Please let us know if you have any other questions.

on March 3, 2020

Hello,While I understand why D is correct, I don't understand why B is incorrect.

If I place Z on Tuesday, that leaves me with the following:

Monday: H

Tuesday: Z & (K / O)

Wednesday: (O / K)

Thursday: I

Friday: U

Since I've already used up my 2 session/day rule, doesn't that mean I have only Friday left for U?

Can someone please help me?

Thanks!

Skyler on July 8, 2020

Can someone explain B is incorrect?Victoria on July 9, 2020

Hi @VPH and @Skyler-Simon,Happy to help!

@VPH you've missed a possibility in your diagram. We know that the double session cannot be scheduled on Monday or Wednesday, but it is possible for it to be scheduled on Thursday.

Therefore, (B) is incorrect because it is also possible for U to be scheduled on Wednesday if we schedule Z on Thursday.

Monday: H

Tuesday: Z

Wednesday: U

Thursday: I & (K/O)

Friday: O/K

Hope this helps! Please let us know if you have any further questions.

Francisco on July 14, 2020

Hello @Victoria,I am still a bit confused as to how we know to go straight to Thursday. I understand how that works out but I had the same question as above. Hopefully I'll be able to explain it well.

In the game setup video we wrote out all of the different possibilities since the only days there can be two sessions is Tuesday, Wednesday, and Thursday. The setup for having two sessions on Tuesday looked like this:

Monday: _

Tuesday: K/O & _

Wednesday: _

Thursday: I

Friday: U/Z

The question asks where Z could be placed that would force U on Friday. I chose answer B because it seemed to work and it was the very first scenario that we got from the game setup. The completed schedule looked like this for me:

Monday: H

Tuesday: K/O & Z

Wednesday: O/K

Thursday: I

Friday: U

I understand that even with the three setups we initially had that this is far from a GURU game but I am still lost as to how B is incorrect?

Maybe another way of asking is how do we know that placing Z on Thursday is the most restrictive? After reading the question I looked back at the setup and having Tuesday with two sessions was the first one and at first glance it seemed to work.

Thank you for your help.

Victoria on July 14, 2020

Hi @fdaniel,Happy to help!

I think you may have misinterpreted the question a little bit. We are not looking for the placement of Z which forces U to be scheduled on Friday. We are looking for the placement of Z which conclusively determines the day on which U must be scheduled i.e. if Z is scheduled on X, then there is only one possible day that U can be scheduled.

Answer choice (B) is incorrect because, if we schedule Z on Tuesday, then U could be scheduled on either Friday or Wednesday.

Option 1

Monday: H

Tuesday: K/O & Z

Wednesday: O/K

Thursday: I

Friday: U

Option 2

Monday: H

Tuesday: Z

Wednesday: U

Thursday: I & K/O

Friday: O/K

Alternatively, if we schedule Z on Thursday, then there is only one possible day that U can be scheduled.

We know that I must be scheduled on Thursday. Therefore, Thursday is the day with two sessions.

U must be scheduled on Friday for two reasons: (1) K and O must be scheduled on consecutive days - as Thursday is full, K and O must be scheduled on either M/T or T/W; and (2) H must be scheduled before Z.

In this way, while there are two different options, H, K, and O must be scheduled on Monday, Tuesday, and Wednesday in both. This means that U can only be scheduled on Friday.

Option 1

Monday: H

Tuesday: K/O

Wednesday: O/K

Thursday: Z & I

Friday: U

Option 2

Monday: K/O

Tuesday: O/K

Wednesday: H

Thursday: Z & I

Friday: U

Hope this helps clear things up a bit! Please let us know if you have any further questions.