June 2007 LSAT Section 1 - Logic Game 2

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Turning our attention to question number ten, the last question of this game. If

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the Limelight is shown exactly three times and if Harvest is shown exactly

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twice and Greed is shown exactly once. Which one of the following is a complete

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and accurate list of films that could be the first shown on Thursday? Alright, so

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let's draw out this scenario here again we know that if we have Limelight showing

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up three times

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Limelight is going to appear on every day and we know that on Friday Limelight is

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going to have to be second which means Greed is not going to appear which puts

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Harvest as first on Friday and then we know we also have Limelight showing up

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on Saturday. Limelight also is going to show up on Thursday. And now we know we need to have

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two more H's and A G. Well, our possibilities would be as follows. We

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could have another H appear in Thursday which we know must be true and then

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we have Greed show up on Saturday as the second film. But notice that's not the only

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possibility. Again, when I placed Limelight on Friday nothing said I had

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to have another film there. So, instead of handy my second Harvest appear on Friday

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why not have the second Harvest appear on Saturday. And now I can also have all

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three appear on Thursday. So, looking at these two scenarios again we're looking

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for a complete and accurate list of the films that could be the first film

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shown on Thursday and you notice G and L

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are the only possibilities for the first film on Thursday. In this scenario we had G and L

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In this scenario L is the only possibility. So, D, G, and L would be the correct answer.

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And that is the end of this game. I hope that was helpful.

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Let's move on to the third game of the June 2007 LSAT exam.

June 2007 - Sec 1 - Game 2 - Q10