# June 2007 - Sec 1 - Game 3 - Q17

## Video Transcript:

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Which brings us to question 17 the final question in this game. Which one of the
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following must be true about Freedom's schedule of voyages? And this is a fabulous
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example of the time trap question. Coming out and asking you what must be true. Alright so
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first we want to try to use previous hypotheticals as counter examples to
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eliminate as many answer choices as possible But again before checking every answer choice we want to
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scan them as well to make sure we haven't already made this deduction.
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So let's take a closer look at the answer choices turning our attention first to (A). Freedom
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makes a voyage to Guadaoupe either in week 1 or else in week 2. You notice in all of our previous
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work we have Guadaloupe either in week 1 or in week 2 for all of our previous
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hypotheticals. But again that doesn't necessarily mean it must be true.
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We could have a scenario that we haven't drawn out yet but we don't see Guadalupe in
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week 1 or week 2 so let's hold (A). Moving to (B). Freedom makes a voyage to Martinique either in
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week 2 or else in week 3. And if you notice in our previous work from
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question 13 our top scenario week 2 and 3 is G in J. So (B) doesn't have to be true.
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Again coming directly from our previous work from question number 13.
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Turning our attention to (C). Freedom makes at most two voyages to Guadaloupe. Again in none of
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our previous work do we see Guadeloupe more than twice. Again don't forget that in this
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scenario over here these are reverse dual options. We're gonna have one Martinique and one Guadeloupe.
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But that doesn't mean that it must be true. Again there could be a possibility
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where we see three voyages to Gaudeloupe that we just haven't drawn out yet. And again
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we know that having a destination appear three times is clearly a
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possibility. So again we're not going to eliminate (C). Moving to D:
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Freedom makes and most two voyages to Jamaica and
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again we made that deduction in our general setup. Jamaica is maximum going to show up
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twice because of the condition that any time we have Jamaica we must have
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Guadalupe in the week immediately preceding it. So, if we had three Jamaicas we
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would have to have 3 Guadaloupes in each week preceding each Jamaica which is six
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of the seven weeks but we still have to place M and T which clearly does not
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follow. So (D) must be true and (D) would be the correct answer. And again a great example
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of a time trap questions that they're trying to get you to have to go through
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all of these answer choices and check them one at a time and proving that something
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must be true is extremely difficult as you have to show that it's the case in
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every single possible scenario. So again that's why we quickly scan the answer choices looking
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for counter examples from previous work that can eliminate answer choices because they're
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not necessarily true and also looking for any of the major deductions that we
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made like answer choice (D) here that Freedom can make at most two Voyages to Jamaica.
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That is the end of our discussion of the third game. Let's turn our attention now
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to the fourth game of the June 2007 LSAT.