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So, the third game of the June 2007 LSAT states:
A cruise line is scheduling 7

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week-long voyages for the ship Freedom.
Each voyage will occur in exactly one of

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the first 7 weeks of the season

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weeks 1 through 7. Each voyage will be to
exactly one of four destinations: Jamaica,

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Martinique, or Trinidad. Each
destination will be scheduled for at

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least one of the weeks the following
conditions apply to freedom scheduled.

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Alright, first place in what we already know. This
is a seven-week schedule. So, we're going

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to have seven weeks. And we have four
destinations that are possible in

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Guadalupe, Jamaica, Martinique, and
Trinidad and we know that each of these

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will be scheduled for at least one of
the weeks. So, each of these shows up at

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least once. Alright, so let's think about
what that rule is telling us. Each destination

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will be scheduled for at least one of the
weeks and we have four destinations but

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seven weeks which means there are three
weeks that are open. So, let's think about the

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possibilities for the numerical
distribution of these destinations. So, if we

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have three weeks that are open we can
have one of the destinations appear four

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times and the other three appear only
once. We could also have one destination

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appear three times and another
twice and the other two once. And lastly we can have

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three destinations appear twice and one
destination appear one time. And again

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that's coming directly from the rule.
Each destination will be scheduled for

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at least one of the weeks and the fact
that we have weeks one through seven.

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Alright, so now that we have a nice base let's
turn our attention to the conditions that

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are gonna apply to freedoms schedule. The
first condition tells Jamaica will not

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be the destination in week 4. So, we can
write Jamaica is not going to be in week 4.

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The second condition tells us Trinidad
will be the destination in week seven. So,

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we can add Trinidad to week seven.
So, Trinidad is definitely going to be week 7

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but keep in mind it's possible that Trinidad
shows up again.

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Ok. Turning our attention to the third
condition. Freedom will make exactly two

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voyages to Martinique at least one voyage
to Guadalupe will occur in some week between

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those two voyages. Alright, so the third rule
here. What we're seeing is two voyages

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exactly 2 to Martinique. So, you notice
what that does right away is it eliminates

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the 4-1-1 possibility in our numerical
distribution because if Martinique is showing

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up exactly twice in the 4-1-1 one
possibility there is no one showing

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exactly twice. So, that possibility has
been eliminated now based on the third

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condition. Again, the condition is that
there is at least one trip to Guadalupe

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inbetween the two trips to Martinique.
So, we have that block.

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Now, keep in mind we cannot make certain
deductions here. For example, you cannot conclude

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based on the fact that Trinidad is
7th that Martinique cannot appear 5th because again if Martinique appeared fifth

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as long as the other Martinique appears
third or earlier and Guadalupe is in between

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and it's still fine. So, we can't do
anything with that rule. Turning our

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attention now to the fourth condition.
Guadalupe will be its destination in the

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week preceding any Voyage it makes to Jamaica. Alright,
so it's really important to think carefully about

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what this rule is saying because again we know 'any'
introduces sufficient so any voyage it makes to

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must be preceded by a trip to Guadalupe. And we know
for sure there's going to be at least

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one trip to Jamaica. Therefore we know for sure
we are going to have to place this 'G' 'J'

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box at least once in our schedule.
Possibly twice but notice another

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conclusion and we can me is that J can
only show up max twice because if

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Jamaica were to appear 3 times we would
have to have Guadalupe in every week preceding

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those which would be six
destinations already

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of the seven but we also have Martinique
and Trinidad remaining to place so

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that clearly would not work. So Jamaica can
only appear maximum twice. And one last

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Deduction we can make from rule number
four is that Jamaica cannot be first

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because of Jamaica was first we would
not have a week preceding it for Guadalupe.

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And now turning our attention to the fifth and
final condition: No destination will be

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scheduled for consecutive weeks. So,
telling us that we can't have Guadalupe, Jamaica, Martinique,

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or Trinidad in consecutive weeks
and we know since we have Trinidad in

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week 7 that we cannot see Trinidad again
in week 6. And that is the set up for this

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game. The only other thing that you
should be aware of is the placement

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possibilities for our Jamaica / Guadalupe
block. Again, at this point only possibilities

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are 1 and 2. We could also have that
appear two and three and then four and five

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and lastly 5 and 6 and keep in mind

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have J show up twice so we could
actually have two of those blocks in our

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game so let's turn our attention now to
the questions...